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问题描述:
若实数x≠y,且x的平方-2x+y=0,y的平方-2y=X=0,求x+y的值.
相减 x²-2x+y-y²+2y-x=0-0 x²-y²-3x+3y=0 (x+y)(x-y)-3(x-y)=0 (x-y)(x+y-3)=0 x≠y则x-y≠0 所以x+y-3=0 x+y=3