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问题描述:
已知(4x-2y-1)^2+根号xy-2=0,求4x^2y-4x^2y^2-2xy^2的值
(4x-2y-1)^2+根号xy-2=0 4x-2y-1=0 xy-2=0 2x-y=1/2 xy=2 4x^2y-4x^2y^2-2xy^2 =2xy(2x-2xy-y) =2*2(1/2-4) =4*-7/2 =-14